2026 WAEC GCE FIRST SERIES (JANUARY) FURTHER MATHEMATICS: WAEC GCE first series 2026 FURTHER MATHEMATICS ANSWERS (8175)
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WAEC GCE first series 2026 FURTHER MATHEMATICS ANSWERS Password/Pin/Code: 8175.
Tuesday 7th May, 2019
Further Mathematics/Mathematics (Elective) 2 (Essay) 30mins 09:30 a.m 12:00 noon
Further Mathematics/Mathematics (Elective) 1 (Objective) 30mins 3:30p.m 5:00 p.m.
FURTHER MATHS OBJ:
1-10: AACACBDABC
11-20: DAACCDBDAA
21-30: BCCBABABCC
31-40: BCCBCCDDDD
Welcome to official 2026 Further Mathematics WAEC GCE First Series (January) answer page. We provide 2026 Further Mathematics WAEC GCE First Series (January) Questions and Answers on Essay, Theory, OBJ midnight before the exam, this is verified & correct WAEC GCE First Series (January) Further Maths Expo. WAEC GCE First Series (January) Further Mathematics Questions and Answers 2026. WAEC GCE First Series (January) Further Maths Expo for Theory & Objective (OBJ) PDF: verified & correct expo Solved Solutions, WAEC GCE first series 2026 FURTHER MATHEMATICS ANSWERS. 2026 WAEC GCE First Series (January) EXAM Further Mathematics Questions and Answers
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No1
NUMBER 1 FINAL ANSWER IS 6/26
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(2a)
Using y2 - y1/x2 - x1
Where y2 = 7, y1 = -5,
X2 = -2, and X1 = 7
7 - -5/-2 - 7
=7+5/-9
=12/-9
=4/-3
Coordinate points :
-4/3(3 : 2)
=-12/3 : -8/3
= -4 : -2β
X = (-4, 2β
)
(2b)
2/1-β2 - 2/2+β2
=2(2+β2)-2(1-β2)/(1-β2)(2+β2)
=4+2β2 - 2+2β2/2+β2-2β2 - 2
=2 + 4β2/-β2
=(2+4β2)(-β2)/-β2(-β2)
= -2β2 - 4(2)/2
= -8 - 2β2/2
= -4 - β2
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No3
(3)
Sn = A/2[2n+(n-1)d]
Where Sn = 165
a = -3, d = 2
165 = A/2[2(-3)+(n-1)2]
165 = n[-6+2n-2]/2
165Γ2 = n[2n - 8]
330 = 2n
Welcome to official 2026 Further Mathematics WAEC GCE First Series (January) answer page. We provide 2026 Further Mathematics WAEC GCE First Series (January) Questions and Answers on Essay, Theory, OBJ midnight before the exam, this is verified & correct WAEC GCE First Series (January) Further Maths Expo
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